0=(4x^2)-(x-4)

Solution for 0=(4x^2)-(x-4) equation:

0=(4x^2)-(x-4)

We move all terms to the left:

0-((4x^2)-(x-4))=0

We add all the numbers together, and all the variables

-(4x^2-(x-4))=0


We calculate terms in parentheses: -(4x^2-(x-4)), so:

4x^2-(x-4)

We get rid of parentheses

4x^2-x+4

We add all the numbers together, and all the variables

4x^2-1x+4

Back to the equation:

-(4x^2-1x+4)


We get rid of parentheses

-4x^2+1x-4=0

We add all the numbers together, and all the variables

-4x^2+x-4=0

a = -4; b = 1; c = -4;
Δ = b2-4ac
Δ = 12-4·(-4)·(-4)
Δ = -63
Delta is less than zero, so there is no solution for the equation